### Physics - Simple Harmonic Motion

#### Question - 1

Amplitude is a

• A scalar quantity
• B vector quantity
• C cannot be negative
• D Both (a) and (c) are correct

#### Question - 2

The displacement of particle is represented by equation is represented by equation $y=3cos(\pi/4-2\omega t)$ . The motion of the particle is

• A simple harmonic with period $2\pi/\omega$
• B simple harmonic with period $\pi/\omega$
• C periodic but not simple harmonic
• D non-periodic

#### Question - 3

A particle is performing SHM given by equation $\frac{d^2x}{dt^2}+9x=0$, the time period is

• A $2\pi$
• B $\frac{1}{3}\pi$
• C $\frac{2}{3}\pi$
• D $4\pi$

#### Question - 4

If the maximum velocity in SHM is vmax. Then, the average velocity during motion from one extreme point to the other extreme point will be

• A $\frac{4}{\pi}v_{max}$
• B $\frac{\pi}{4}v_{max}$
• C $\frac{2}{\pi}v_{max}$
• D $\frac{\pi}{2}v_{max}$

#### Question - 5

A body doing SHM with amplitude 1 cm and frequency 60 Hz. The maximum acceleration will be

• A  $200 \quad\pi^2m/s$
• B  $400 \quad\pi^2m/s^2$
• C  $244 \quad\pi^2m/s^2$
• D  $144 \quad\pi^2m/s^2$

#### Question - 6

A body executing SHM of time period 4 s. Time taken by it to move from mean position to half of amplitude starting from the mean position is

• A 4 s
• B $\frac{1}{\sqrt{3}}s$
• C $\frac{1}{3}s$
• D $\frac{2}{3}s$

#### Question - 7

A particle is acted simultaneously by mutually perpendicular forces then nature of simple harmonic motion of the particle will be

• A an ellipse
• B a parabola
• C a circle
• D a straight line

#### Question - 8

The ratio of amplitudes of following SHM is x1=$A \ sin \ \omega t$ and

• A $\sqrt {2}$
• B $\frac{1}{\sqrt{2}}$
• C 1
• D 2

#### Question - 9

A particle executing SHM with frequency v. The frequency with which kinetic energy oscillate is

• A 4v
• B v
• C v/2
• D 2v

#### Question - 10

If <E> and <V> denotes the average kinetic and average potential energies respectively of mass describing a simple harmonic motion over one period, then the correct relation is

• A <E> = <V>
• B <E> = 2<V>
• C <E> = -2<V>
• D <E> = -<V>