### NEET Physics - New - Simple Harmonic Motion

#### Question - 1

A particle executing SHM with frequency v. The frequency with which kinetic energy oscillate is

• A 4 v
• B v
• C v / 2
• D 2 v

#### Question - 2

Assertion (A) If a boy sitting on a swing stands up, the time period of swing decreases.
Reason (R) When boy stands up, more weight is felt on the string of swing.

• A Both Assertion and Reason are true and Reason is the correct explanation of the Asserton
• B Both Assertion and Reason are true but Reason is not the correct explanation of Assertion
• C Asserton is true but Reason is false
• D Both Asserton and Reason are false

#### Question - 3

Assertion (A) The percentage change in time period is 1.5%, if the length of simple pendulum increases by 3%.
Reason (R) Time period is directly proportional to length of pendulum.

• A Both Assertion and Reason are true and Reason is the correct explanation of the Assertion
• B Both Assertion and Reason are true but Reason is not the correct explanation of Asertion
• C Assertion is true but Reason is false
• D Both Assertion and Reason are false

#### Question - 4

The distance covered by a particle in simple harmonic motion in one time period is

• A zero
• B 4A
• C 2A
• D A

#### Question - 5

The displacement of a particle is represented by equation $y=3 \cos (\pi / 4-2 \omega t)$. The motion of the particle is

• A simple harmonic with period $2 \pi / \omega$
• B simple harmonic with period $\pi / \omega$
• C periodic but not simple harmonic
• D non-periodic

#### Question - 6

A particle is performing SHM given by equation $\frac{d^2 x}{d t^2}+9 x=0$then time period is

• A $2 \pi$
• B $\frac{1}{3} \pi$
• C $\frac{2}{3} \pi$
• D $4 \pi$

#### Question - 7

If the maximum velocity in SHM is vmax Then, the average velocity during motion from one extreme point to the other extreme point will be

• A $\frac{4}{\pi} v_{\max }$
• B $\frac{\pi}{4} v_{\max }$
• C $\frac{2}{\pi} v_{\max }$
• D $\frac{\pi}{2} v_{\max }$

#### Question - 8

A particle executing SHM on X-axis with origin as mean position, then graph of speed (v) versus displacement (x)will be

• A parabola
• B ellipse
• C circle
• D hyperbola

#### Question - 9

A body doing SHM with amplitude 1 cm and frequency 60 Hz. The maximum acceleration will be

• A $200 \pi^2 \mathrm{~m} / \mathrm{s}^2$
• B $400 \pi^2 \mathrm{~m} / \mathrm{s}^2$
• C $244 \pi^2 \mathrm{~m} / \mathrm{s}^2$
• D $144 \pi^2 \mathrm{~m} / \mathrm{s}^2$

#### Question - 10

A body executing SHM of time period 4 s. Time taken by it to move from mean position to half of amplitude starting A body executing SHM of time periodv4 s. Time taken by it to move from meanvposition to half of amplitude startingvfrom the mean position isfrom the mean position is

• A 4 s
• B $\frac{1}{\sqrt{3}}$ s
• C $\frac{1}{3} \mathrm{~s}$
• D $\frac{2}{3} \mathrm{~s}$