#### Question - 4

Four particle of masses, m, 2 m, 3 m and 4 m are arranged at the corners of a parallogram with each side equal to a and one of the angle between two adjacent sides is \({ 60 }°\) . The parallelogram lies in the xy plane with mass m at the origin and 4 m on the X-axis, The centre of mass of the arrangement will be located at

- A \((\frac { \sqrt { 3 } }{ 2 } a,0.95a)\)
- B \((0.95a,\frac { \sqrt { 3 } }{ 4 } a)\)
- C \((\frac { 3a }{ 4 } ,\frac { a }{ 2 } )\)
- D \(( \frac { a }{ 2 } ,\)\(\frac { 3a }{ 4 } )\)