JEE Main Chemistry - SI Units Significant Figures Equivalent Mass Atomic Mass Mole Concept and Chemical Calculations
Exam Duration: 60 Mins Total Questions : 30
71 g of chlorine gas forms 136 g of metal chloride. The equivalent weight of metal is
- (a)
32.5
- (b)
65
- (c)
97.5
- (d)
130
50 ml of LiOH can completely neutralise 25 ml of 2M phoshoric acid. The molarity of LiOH is
- (a)
1
- (b)
2
- (c)
3
- (d)
5
KMnO4, on reaction with dilute sulphric acid gives oxygen. The equivalents of oxygen produced per mole of KMnO4 is
- (a)
2
- (b)
2.5
- (c)
4
- (d)
5
Weight of 1000 ml of a gas is 0.7171 g. Molecular mass of gas is
- (a)
8
- (b)
16
- (c)
24
- (d)
32
For neutralising 0.183 g of a monobasic acid dissolved in water, 15 ml of N/190 NaOH were required. The molecular mass of acid is
- (a)
63
- (b)
90
- (c)
122
- (d)
140
With how much of oxygen 27 g of Al reacts completely?
- (a)
16 g
- (b)
24 g
- (c)
32 g
- (d)
48 g
10 ml of 1M NaOH solution neutralises 1M H2SO4; the volume of acid is
- (a)
3 ml
- (b)
4 ml
- (c)
5 ml
- (d)
10 ml
A gaseous mixture contains oxygen and nitrogen in tha ratio of 1 : 4 by weight ; the ratio of number of molecules will be
- (a)
1 : 7
- (b)
2 : 9
- (c)
7 : 32
- (d)
3 ; 16
Chloride of an element contains 92.21 % of chloride by weight. Its v.d. is 77. The at. wt. of the element is
- (a)
12
- (b)
24
- (c)
36
- (d)
48
A metal is burnt in O2; all the products of the combustion are weighed. It is found that the weight of the metal seems to have increased by 24%. The at. wt. of metal would be
- (a)
24
- (b)
27
- (c)
33.34
- (d)
None of these
4 g of NaOH was dissolved in 100 ml of water. The whole of this solution will neutralise completely.
- (a)
100 ml of 0.5 M H2SO4
- (b)
20 ml of 2.5 M H2SO4
- (c)
30 ml of 5 N H2SO4
- (d)
40 ml of 5 M H2SO4
The molecular weight of KMnO4 is 158. The equivalent weight of KMnO4 in acidic and neutral medium respectively are
- (a)
158, 158
- (b)
31.6, 31.6
- (c)
31.6, 52.6
- (d)
52.6, 52.6
Which one of the following is not related correctly in SI units?
- (a)
1.35 mm = 1.35 x 10-3 m
- (b)
6.45 m L = 6.45 x 10-3 L
- (c)
48\(\mu g\) = 4.8 x 10-5 g
- (d)
0.426 inch = 1.08 x 10-3 m
Which is an example of law of multiple proportion:
- (a)
NO, NO2, N2O3 , N2O4, N2O5
- (b)
H2O, H2O2
- (c)
CuO, Cu2O
- (d)
All of these
What is the mass in grams of 0.25 mol copper?
Cu = 63.5 a.m.u.
- (a)
8
- (b)
16
- (c)
24
- (d)
32
The density of liquid gallium metal is 6.1 g/cm3. What is the approximate volume occupied by 25 gallium atoms ? Ga = 69.72 a.m.u.
- (a)
2.35 x 10-22 cm3
- (b)
18.8 x 10-22 cm3
- (c)
9.4 x 10-22 cm3
- (d)
4.7 x 10-22 cm3
How many oxygen atoms are there in 6.025 g. Ba3(PO4)2 ? Ba = 137.5, P = 31, O =16
- (a)
9.6 x1022
- (b)
4.8 x1022
- (c)
2.4 x1022
- (d)
1.2 x1022
What is the mass of one ammonia molecule? N = 14, H = 1
- (a)
1.4 x 10-23 g
- (b)
2.8 x 10-23 g
- (c)
5.6 x 10-23 g
- (d)
7.0 x 10-23 g
For the preparation of 0.6 mol of K2Cr2O7, the number of potassium atoms required are
- (a)
2.0 x 1023
- (b)
7.22 x 1023
- (c)
6.02 x 1023
- (d)
3.01 x 1024
27 g of Al will react completely with
- (a)
24 g of oxygen
- (b)
32 g of oxygen
- (c)
16 g of oxygen
- (d)
8 g of oxygen
How many moles of lead nitrate are required to produce 48 g of oxygen?
- (a)
4 moles
- (b)
3 moles
- (c)
2 moles
- (d)
1 mole
The largest number of molecules is in
- (a)
36 g of water
- (b)
28 g of CO2
- (c)
46 g of CH3OH
- (d)
54 g of N2O5
Volume of a gas at NTP is 1.12 x 10-7 cc. Calculate the number of molecules in it.
- (a)
3.01 x 1020
- (b)
3.01 x 1012
- (c)
30.1 x 1023
- (d)
3.01 x 1024
The number of moles of oxygen in 1L of air containing 21 % oxygen by volume, in standrad conditions, is
- (a)
0.186 mol
- (b)
0.21 mol
- (c)
2.10 mol
- (d)
0.0093 mol
2 g of oxygen contains number of atoms equal to that in
- (a)
0.5 g of hydrogen
- (b)
4 g of sulphur
- (c)
7 g of nitrogen
- (d)
2.3 g of sodium
Which of the following has the smallest number of molecules?
- (a)
0.1 mol of CO2 gas
- (b)
11.2 L of CO2 gas at NTP
- (c)
22 g of CO2 gas
- (d)
22.4 x 103 ml of CO2 gas
Which of the following has the largest number of atoms?
- (a)
0.5 g atoms of Cu
- (b)
0.635 g of Cu
- (c)
0.25 moles of Cu atoms
- (d)
1 g of Cu
The number of gram- molecules of oxygen in 6.02 x 1024 CO molecules is :
- (a)
10 g-molecules
- (b)
5 g-molecules
- (c)
1 g-molecule
- (d)
0.5 g-molecule
Two elements, X ( at. mass 75) and Y ( at. mass 16) combine to give a compound having 78.8% X. The formula of the compound is :
- (a)
XY
- (b)
X2Y
- (c)
X2Y2
- (d)
X2Y3
If 1021 molecules are removed from 200 mg of CO2, then the number of moles of CO2 left are :
- (a)
2.88 x 10-3
- (b)
1.66 x 10-3
- (c)
4.54 x 10-3
- (d)
1.66 x 10-3