Stress and Strain
Exam Duration: 45 Mins Total Questions : 20
Relation between E, K and G is given by
- (a)
\(E=\frac{9KG}{3K+G}\)
- (b)
\(E=\frac{3K+G}{6KG}\)
- (c)
\(E=\frac{6KG}{K+3G}\)
- (d)
\(E=\frac{3KG}{3K+G}\)
Strain in a direction at right angle to the direction of applied force is known as
- (a)
lateral strain
- (b)
shear strain
- (c)
volumetric strain
- (d)
None of these
Maximum stress (\(\sigma_{max}\)) induced in a bar of length l, rotating at an angular velocity \(\omega\) , is given by
- (a)
\(\frac{1}{2}\rho \omega^2l^2\)
- (b)
\(\frac{1}{8}\rho \omega^2l^2\)
- (c)
\(\rho \omega^2l^2\)
- (d)
\(\rho \omega^2l^2\)
However complex the state of stress may be in a body the number of principal planes are always
- (a)
2
- (b)
3
- (c)
4
- (d)
1
The normal stress on a plane whose normal is inclined at angle θ with the line of action of the uniaxial stress σx is given by
- (a)
σx l cos2θ
- (b)
σx l sin2θ
- (c)
σx cos2θ
- (d)
σx sin2θ
If the angle between the two planes is θ, then the angle between the normal stress and the resultant stress on the oblique planes in the case of uniaxial stress is
- (a)
\(\frac{\theta}{2}\)
- (b)
\(\theta\)
- (c)
\(2\theta\)
- (d)
\(\frac{\theta}{4}\)
In the case of biaxial state of normal stresses, the maximum shear stress is equal to
- (a)
the sum of the normal stresses
- (b)
the difference of normal stresses
- (c)
half the difference of normal stresses
- (d)
half the sum of normal stresses
For a two dimensional stress system, the coordinates of the centre of Mohr's circle are
- (a)
\((\frac{\sigma_X-\sigma_Y}{2},0)\)
- (b)
\((0,\frac{\sigma_X+\sigma_Y}{2})\)
- (c)
\((\frac{\sigma_X+\sigma_Y}{2},0)\)
- (d)
\((0,\frac{\sigma_X-\sigma_Y}{2})\)
A point in two dimensional stress state, is subjected to biaxial stress as shown in the given figure. The shear stress acting on the plane AB is
- (a)
zero
- (b)
\(\sigma\)
- (c)
\(\sigma cos^2\theta\)
- (d)
\(\sigma sin\theta cos\theta\)
In the given figure, the principal stresses are
- (a)
equal in magnitude to the shear stress and similar in nature
- (b)
equal in magnitude to the shear stress and opposite in nature
- (c)
equal in magnitude to half the maximum shear stress at the point and similar in nature
- (d)
equal in magnitude to half the maximum shear stress at the point and opposite in nature
If one of the principal stresses at a point is zero, the magnitude of the other principal stress must be ... the magnitude of maximum shear stress at the point.
- (a)
equal to
- (b)
one and half times
- (c)
twice
- (d)
two and a half times
Match List I with List II and select the correct answer using the codes given below the lists
List I | List II |
---|---|
1.Pure uniaxial compression | |
2.Pure shear | |
3.Pure biaxial tension having sam e magnitude | |
4.Pure biaxial tension |
- (a)
P Q R S 1 2 3 4 - (b)
P Q R S 4 3 2 1 - (c)
P Q R S 2 4 1 3 - (d)
P Q R S 2 1 3 4
The radius of the Mohr's circle gives the value of
- (a)
maximum normal stress
- (b)
minimum normal stress
- (c)
maximum shear stress
- (d)
minimum shear stress
If principal stresses are as σx=65 MN/m2, σy=+20 MN/m2 , σz =-85 MN/m2 and μ=0.3, E=200 GN/m2, then principal strain ex is
- (a)
0.422x10-3
- (b)
0.13x10-3
- (c)
0.552x10-3
- (d)
None of these
In the given figure, \(\frac{E_{Al}}{E_{Cu}}=2,\frac{l_2}{l_1}=1.5, d_{Cu}=30mm, d_{Al}=37.5mm\) . If bar remains horizontal after load P is applied, then ratio of forces in the bar, ρAl/ρCu is
- (a)
1.2
- (b)
3.7
- (c)
2.08
- (d)
4.1
In given figure,
AAl=2 mm2, ACu =1 mm2 and EAl /ECu=2
A load P = 10 kN is applied at a distance b from AI rod, such that bar 1 remains horizontal. Select the correct option
- (a)
σAl=σCu
- (b)
ρAl=ρCu
- (c)
eAl=eCu
- (d)
All of these
In given figure,
AAl=2 mm2, A Cu =1 mm2 and E Al /ECu=2
A load P = 10 kN is applied at a distance b from AI rod, such that bar 1 remains horizontal. Value of b is
- (a)
170 mm
- (b)
106 mm
- (c)
110 mm
- (d)
152 mm
In the given figure,
Principal stresses are
- (a)
112 N/mm2, 67.64 N/mm2
- (b)
100 N/mm2 , 60 N/mm2
- (c)
120 N/mm2, zero
- (d)
zero, -100 N/mm2
In the given figure,
Maximum shear stress is
- (a)
110 N/mm2
- (b)
44.36 N/mm2
- (c)
62 N/mm2
- (d)
77.63 N/mm2
If E=200 GPa and μ=0.283 for this block material then, change in volume due to these complex stresses is
- (a)
100 mm3
- (b)
120 mm3
- (c)
125 mm3
- (d)
135 mm3