Logarithms
Exam Duration: 45 Mins Total Questions : 30
The value of log2 16 is:
- (a)
\(1\over 8\)
- (b)
4
- (c)
8
- (d)
16
The value of log343 7 is:
- (a)
\(1\over 3\)
- (b)
-3
- (c)
\(-\frac { 1 }{ 3 } \)
- (d)
3
The value of \(log_{ \sqrt { 2 } }\quad 32\) is:
- (a)
\(5\over 2\)
- (b)
5
- (c)
10
- (d)
\(1\over 10\)
The value of log10(.0001) is:
- (a)
\(1\over 4\)
- (b)
\(-\frac { 1 }{ 4 } \)
- (c)
-4
- (d)
4
The logrithm of 0.0625 to the base 2 is:
- (a)
-4
- (b)
-2
- (c)
0.25
- (d)
0.5
If log8 x=\(2\over 3\), then the value of x is:
- (a)
\(3\over 4\)
- (b)
\(4\over 3\)
- (c)
3
- (d)
4
If logx(\(9\over 16\))=-\(1\over 2\), then x is equal to :
- (a)
\(-\frac { 3 }{ 4 } \)
- (b)
\(3\over 4\)
- (c)
\(81\over 256\)
- (d)
\(256\over 81\)
If logx 4=\(1\over 4\), then x is equal to:
- (a)
16
- (b)
64
- (c)
128
- (d)
256
If log32x=0.8, then x is equal to :
- (a)
25.6
- (b)
16
- (c)
10
- (d)
12.8
The value of log2(log5 625) is :
- (a)
2
- (b)
5
- (c)
10
- (d)
15
If ax=by, then:
- (a)
log \(a \over b\)=\(x \over y\)
- (b)
\(\frac { log\quad a }{ log\quad b } =\frac { x }{ y } \)
- (c)
\(\frac { log\quad a }{ log\quad b } =\frac { y }{ x } \)
- (d)
none of these
Log 360 is equal to:
- (a)
2 log 2+ 3 log 3
- (b)
3 log 2+2 log 3
- (c)
3 log 2 + 2 log 3 - log 5
- (d)
3 log 2 + 2 log 3 + log 5
2 log10 5+log10 8-\(1 \over 2\)log10 4=?
- (a)
2
- (b)
4
- (c)
2+2 log102
- (d)
4-4 log102
If log8 x +log8 \(\frac { 1 }{ 6 } =\frac { 1 }{ 3 } ,\) then the value of x is
- (a)
12
- (b)
16
- (c)
18
- (d)
24
If log10 125+log10 8=x, then x is equal to :
- (a)
\(1 \over 3\)
- (b)
.064
- (c)
-3
- (d)
3
If log4 x+log2 x =6, then x is equal to
- (a)
2
- (b)
4
- (c)
8
- (d)
16
The value of (log9 27 + log8 32) is:
- (a)
\(7 \over 2\)
- (b)
\(19 \over 6\)
- (c)
4
- (d)
7
(log5 5) (log4 9)(log32) is equal to :
- (a)
1
- (b)
\(3 \over 2\)
- (c)
2
- (d)
5
If log5(x2+x)-log5(x+1)=2, then the value of x is:
- (a)
5
- (b)
10
- (c)
25
- (d)
32
If log107 =a, then log10(\(1 \over 70\)) is equal to:
- (a)
-(1+a)
- (b)
(1+a)-1
- (c)
\(a \over 10\)
- (d)
\(1 \over 10a\)
If a=bx, b=cy and c=az, then the value of xyz is equal to
- (a)
-1
- (b)
0
- (c)
1
- (d)
abc
If log10 2=0.3010, then log2 10 is equal to:
- (a)
\(699 \over 301\)
- (b)
\(1000 \over 301\)
- (c)
0.3010
- (d)
0.6990
If log 3=0.477 and (1000)x=3, then x equals:
- (a)
0.0159
- (b)
0.0477
- (c)
0.159
- (d)
10
If log102=0.3010, the value of log10 25 is:
- (a)
0.6020
- (b)
1.2040
- (c)
1.3980
- (d)
1.5050
If log10 2=0.3010 and log10 7=0.8451, then the value of log10 2.8 is:
- (a)
0.4471
- (b)
1.4471
- (c)
2.4471
- (d)
none of these
If log (0.57) = \(\overline { 1 } .756\), then the value of log 57 + log (0.57)3 + log \(\sqrt{0.57}\) is :
- (a)
0.902
- (b)
\(\overline { 2 } .146\)
- (c)
1.902
- (d)
\(\overline { 1 } .146\)
If log 2 = 0.30103, the number of digits in 264 is :
- (a)
18
- (b)
19
- (c)
20
- (d)
21
If log 2 = 0.30103, the number of digits in 450 is :
- (a)
30
- (b)
31
- (c)
100
- (d)
200
If log12 27 = a, then log6 16 is :
- (a)
\(3-\alpha \over 4(3+\alpha)\)
- (b)
\(3+\alpha \over 4(3-\alpha)\)
- (c)
\(4(3+\alpha) \over (3-\alpha)\)
- (d)
\(4(3-\alpha) \over (3+\alpha)\)
\(\left[ \log { \left( \frac { { a }^{ 2 } }{ bc } \right) } +\log { \left( \frac { { b }^{ 2 } }{ ac } \right) +\log { \left( \frac { c^{ 2 } }{ ab } \right) } } \right] \)is equal to :
- (a)
0
- (b)
1
- (c)
2
- (d)
abc