The product of two natural numbers is 17. Then, the sum of the reciprocals of their squares is
\(\frac { 1 }{ 289 } \)
\(\frac { 289 }{ 290 } \)
\(\frac { 290 }{ 289 } \)
289
If, \(x+\frac { 1 }{ x } =3\) then the value of x6+\(\frac { 1 }{ { x }^{ 6 } } \) is
927
114
364
322
ax2+bx+c=0, where a,b and c are real roots, if
c = 0
b2>3ac
a, b, c are integers
ac>0, and b is zero
The number of real roots of quadratic equation x2-3|x|-10 = 0 is
1
2
3
4
If one root of the two quadratic equations x2+ax+b=0 and x2+bx+a=0 is common, then
a + b = 1
a + b = -1
ab = 1
ab = -1
If the equation x2 - kx + 1 = 0, has no real roots then
-2<k<2
-3<k<3
-4<k<4
none of these
If \(\alpha\) and \(\beta\) are the roots of quadratic equation x2-2x+1, then \(\alpha\)2+\(\beta\)2 is
-2
Find the nature of the roots of the quadratic equation \({ 3x }^{ 2 }-4\sqrt { 3 } x+4=0\)
\(2\frac { \sqrt { 3 } }{ 3 } ,2\frac { \sqrt { 3 } }{ 3 } \)
\(2\frac { \sqrt { 3 } }{ \sqrt { 3 } } ,2\frac { \sqrt { 3 } }{ \sqrt { 3 } } \)
\(2\frac { \sqrt { 3 } }{ 3 } ,-2\frac { \sqrt { 3 } }{ 3 } \)
None of these
Solve 5(x+1) + 5(2-x) = 53+1
2, -1
-2, 1
-2, -1
A total number of 324 coins of 20 paise and 25 paise makes a sum of Rs 71. The number of 25 paise coins
120
124
37
40
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